What will be the output given program?#includevoid main(){ int i = -10; for(;i;printf("%d ", i++));}a)-10 to -1b)-10 to infinitec)-10 to 0d)Complier errorCorrect answer is option 'A'. Can you explain this answer?

Question

What will be the output given program?#include<stdio.h>void main(){ int i = -10; for(;i;printf("%d ", i++));}a)-10 to -1b)-10 to infinitec)-10 to 0d)Complier errorCorrect answer is option 'A'. Can you explain this answer?

Answer

Explanation:

Initialization:
- The variable i is initialized to -10.

For Loop:
- In the for loop condition, the expression i is evaluated.
- Since i is a non-zero value (-10), it is considered as true and the loop continues.

Loop Body:
- Inside the loop, the value of i is printed using the printf function.
- Then, i is incremented by 1 using the post-increment operator (i++).

Loop Iteration:
- The loop continues to run as long as the condition i is true.
- Since i is a non-zero value, the loop continues to print the value of i.

Output:
- The loop will continue to print the values of i starting from -10 and incrementing by 1 each time.
- The output will be: -10 -9 -8 -7 -6 -5 -4 -3 -2 -1
Therefore, the correct answer is option 'a' which states that the output will be -10 to -1.

Answer

for loop can be initialized outside of the loop. Since until -1 value of i remain a non-zero value and hence the condition is true up to -1. But when i is further increases its value becomes 0 and condition becomes false and loop stops there.

Note:In C any non-zero value(positive or negative) evaluates to true and only zero value is evaluates to false.

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